300-435 Question 23
Select 3A network automation engineer has written the following Python script to process a list of device IPs and check if they belong to a specific subnet. Based on the script below, what will be the output?
class SubnetChecker:
def __init__(self, subnet):
self.subnet = subnet
def is_in_subnet(self, ip):
return ip.startswith(self.subnet)
ips = ["192.168.1.10", "192.168.2.20", "192.168.1.15", "10.0.0.5"]
checker = SubnetChecker("192.168.1.")
for ip in ips:
if checker.is_in_subnet(ip):
print(f"{ip} is in the subnet")
else:
print(f"{ip} is not in the subnet")
- A
192.168.1.10 is in the subnet
- B
192.168.2.20 is not in the subnet
- C
192.168.1.15 is not in the subnet
- D
10.0.0.5 is in the subnet
- E
192.168.1.15 is in the subnet
Show answer and explanation
Correct answers: A, B, E
Explanation
The script uses a class called SubnetChecker to determine if an IP address belongs to a specific subnet. The 'is_in_subnet' method checks if the given IP address starts with the subnet string provided during the class instantiation. By iterating through the list of IP addresses, the script prints whether each IP is in or not in the subnet based on the result of the 'is_in_subnet' method. The correct answers reflect the accurate evaluation of each IP against the specified subnet '192.168.1.'.
- A. Correct.
Correct: The IP '192.168.1.10' starts with '192.168.1.' and matches the subnet, so it is correctly identified as being in the subnet.
- B. Correct.
Correct: The IP '192.168.2.20' does not start with '192.168.1.' and does not match the subnet, so it is correctly identified as not being in the subnet.
- C. Incorrect.
Incorrect: The IP '192.168.1.15' starts with '192.168.1.' and matches the subnet, so this statement is incorrect.
- D. Incorrect.
Incorrect: The IP '10.0.0.5' does not start with '192.168.1.' and does not match the subnet, so this statement is incorrect.
- E. Correct.
Correct: The IP '192.168.1.15' starts with '192.168.1.' and matches the subnet, so it is correctly identified as being in the subnet.